运行时查看流程图时会显示流程执行者等显示，波特图中也会显示，但是发通知时设置的通知接收者是不会显示的，如果需要显示如下实现
1.在process组件的onAfterAdvance事件中获取接收人并存储

	public static void noticeFlowProcessAfterAdvance() {
		String sNoticeExecutors = "";
		ProcessControl flowControl = (ProcessControl) ContextHelper.getActionContext().getParameter("control");
		List<ProcessControlItem> listToItem = flowControl.getNotices();//获取当前环节流程时所有的通知
		for(int j = 0;j<listToItem.size();j++){//遍历所有的通知获取对应的执行者拼接字符串
			if(j != 0)
				sNoticeExecutors = sNoticeExecutors+",";
			ProcessControlItem to = listToItem.get(j);
			List<OrgUnit> list = to.getExecutors();		
			for(int i = 0;i<list.size();i++){
				OrgUnit ect = list.get(i);
				String fname = ect.getFName();
				if(i +1 == list.size())
					sNoticeExecutors += fname;
				else
					sNoticeExecutors += fname+",";	
			 }
		}
		if(Utils.isNotEmptyString(sNoticeExecutors)){			
			String taskID = ProcessUtils.getTaskInProcessContext().getId();//获取当前任务ID
			String ksql = "update SA_Task task set task.sETField34 ='"+sNoticeExecutors+"' where task = '"+taskID+"'";//把拼接的执行者字符串复制给当前任务的sETField34
			KSQL.executeUpdate(ksql, null, "/system/data", null);
		}
	}

2.修改/UI2/system/service/process/dialog/processChart.w文件文件，可以参考http://docs.wex5.com/bex5-process-processchart10021/中方式添加上sETField34，运行时就会把存储的接收通知的人显示出来,如下：
task

task2